Orthogonal complement

From Maths
Revision as of 04:07, 8 April 2017 by Alec (Talk | contribs) (Saving work)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to: navigation, search
Stub grade: B
This page is a stub
This page is a stub, so it contains little or minimal information and is on a to-do list for being expanded.The message provided is:
Proper stub Alec (talk) 04:07, 8 April 2017 (UTC)

Definition

Let [ilmath]((X,[/ilmath][ilmath]\mathbb{K} [/ilmath][ilmath]),\langle\cdot,\cdot\rangle)[/ilmath] be an inner-product space and let [ilmath]L[/ilmath] be a vector subspace of the vector space [ilmath](X,\mathbb{K})[/ilmath][Note 1], then we may define the orthogonal complement of [ilmath]L[/ilmath], denoted [ilmath]L^\perp[/ilmath], as follows[1]:

  • [ilmath]L^\perp:\eq\Big\{x\in X\ \Big\vert\ \forall y\in L[[/ilmath][ilmath]\langle x,y\rangle\eq 0[/ilmath][ilmath]]\ \Big\} [/ilmath] - notice that [ilmath]\langle x,y\rangle\eq 0[/ilmath] is the definition of [ilmath]x[/ilmath] and [ilmath]y[/ilmath] being orthogonal vectors, thus:
    • the orthogonal complement is all vectors which are orthogonal to the entire of [ilmath]L[/ilmath].

Properties

Notes

  1. TODO: Can we relax this to a subset maybe?
  2. The topology we consider [ilmath](X,\langle\cdot,\cdot\rangle)[/ilmath] with is the topology induced by the metric [ilmath]d(x,y):\eq\Vert x-y\Vert[/ilmath] which is the metric induced by the norm [ilmath]\Vert x\Vert:\eq \sqrt{\langle x,x\rangle} [/ilmath] which itself is the norm induced by the inner product [ilmath]\langle\cdot,\cdot\rangle[/ilmath]

References

  1. Warwick 2014 Lecture Notes - Functional Analysis - Richard Sharp