First group isomorphism theorem

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Note:
First isomorphism theorem
Where \theta is an isomorphism.
Properties
something

Statement

Let (G,*) and (H,*) be groups. Let \varphi:G\rightarrow H be a group homomorphism, then[1]:

  • G/\text{Ker}(\varphi)\cong\text{Im}(\varphi)
    • Explicitly we may state this as: there exists a group isomorphism between G/\text{Ker}(\varphi) and \text{Im}(\varphi).

Note: the special case of \varphi being surjective, then \text{Im}(\varphi)=H, so we see G/\text{Ker}(\varphi)\cong H

Useful corollaries

  1. An injective group homomorphism means the group is isomorphic to its image
    • If \varphi:A\rightarrow B is an injective group homomorphism then A\cong \text{Im}(\varphi)
  2. A surjective group homomorphism means the target is isomorphic to the quotient of the domain and the kernel
    • If \varphi:A\rightarrow B is a surjective group homomorphism then A/\text{Ker}(\varphi)\cong B

Proof

Notes

References

  1. Jump up Abstract Algebra - Pierre Antoine Grillet