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I cannot believe it's been 15 months and this still isn't complete!
- Started refactoring Alec (talk) 19:55, 1 November 2016 (UTC)
Definition
Let (X,J) be a topological space Loop(X,b)⊆C(I,X) and consider the relation of path homotopic maps, ((⋅)≃(⋅) (rel {0,1})) on C(I,X) and restricted to \text{Loop}(X,b), then:
- \pi_1(X,b):=\frac{\text{Loop}(X,b)}{\big((\cdot)\simeq(\cdot)\ (\text{rel }\{0,1\})\big)} has a group structure, with the group operation being:
- :[\ell_1]\cdot[\ell_2]\mapsto[\ell_1*\ell_2] where \ell_1*\ell_2 denotes the loop concatenation of \ell_1,\ell_2\in\text{Loop}(X,b).
Proof of claims
[Expand]
Outline of proof that \pi_1(X,b) admits a group structure with \big(:([\ell_1],[\ell_2])\mapsto[\ell_1*\ell_2]\big) as the operation
\xymatrix{
\Omega(X,b)\times\Omega(X,b) \ar@2{->}[d]_{(\pi,\pi)} \ar[rr]^-{*} \ar@/^3.5ex/[drr]^(.75){\pi\circ *} & & \Omega(X,b) \ar[d]^{\pi} \\
\pi_1(X,b)\times\pi_1(X,b) \ar@{.>}[rr]_-{\overline{*} } & & \pi_1(X,b)
}
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Factoring * (loop concatenation) setup
|
Let
(X,\mathcal{ J }) be a
topological space and let
b\in X be given. Then
\Omega(X,b) is the set of all
loops based at
b. Let
{\small(\cdot)}\simeq{\small(\cdot)}\ (\text{rel }\{0,1\}) denote the relation of
end-point-preserving homotopy on
C([0,1],X) - the set of all
paths in
X - but considered only on the subset of
C([0,1],X),
\Omega(X,b).
Then we define: \pi_1(X,b):=\frac{\Omega(X,b)}{\big({\small(\cdot)}\simeq{\small(\cdot)}\ (\text{rel }\{0,1\})\big)}, a standard quotient by an equivalence relation.
Consider the binary function: *:\Omega(X,b)\times\Omega(X,b)\rightarrow\Omega(X,b) defined by loop concatenation, or explicitly:
- *:(\ell_1,\ell_2)\mapsto\left(\ell_1*\ell_2:[0,1]\rightarrow X\text{ given by }\ell_1*\ell_2:t\mapsto\left\{\begin{array}{lr}\ell_1(2t) & \text{for }t\in[0,\frac{1}{2}]\\ \ell_2(2t-1) & \text{for }t\in[\frac{1}{2},1]\end{array}\right.\right)
- notice that t=\frac{1}{2} is in both parts, this is a nod to the pasting lemma
We now have the situation on the right. Note that:
- (\pi,\pi):\Omega(X,b)\times\Omega(X,b)\rightarrow\pi_1(X,b)\times\pi_1(X,b) is just \pi applied to an ordered pair, (\pi,\pi):(\ell_1,\ell_2)\mapsto([\ell_1],[\ell_2])
In order to factor (\pi\circ *) through (\pi,\pi) we require (as per the factor (function) page) that:
- \forall(\ell_1,\ell_2),(\ell_1',\ell_2')\in\Omega(X,b)\times\Omega(X,b)\big[\big((\pi,\pi)(\ell_1,\ell_2)=(\pi,\pi)(\ell_1',\ell_2')\big)\implies\big(\pi(\ell_1*\ell_2)=\pi(\ell_1'*\ell_2')\big)\big], this can be written better using our standard notation:
- \forall\ell_1,\ell_2,\ell_1',\ell_2'\in\Omega(X,b)\big[\big(([\ell_1],[\ell_2])=([\ell_1'],[\ell_2'])\big)\implies\big([\ell_1*\ell_2]=[\ell_1'*\ell_2']\big)\big]
Then we get (just by applying the function factorisation theorem):
- \overline{*}:\pi_1(X,b)\times\pi_1(X,b)\rightarrow\pi_1(X,b) given (unambiguously) by \overline{*}:([\ell_1],[\ell_2])\mapsto[\ell_1*\ell_2] or written more nicely as:
- [\ell_1]\overline{*}[\ell_2]:=[\ell_1*\ell_2]
Lastly we show (\pi_1(X,b),\overline{*}) forms a group
[Expand]
Proof that \pi_1(X,b) admits a group structure with \big(:([\ell_1],[\ell_2])\mapsto[\ell_1*\ell_2]\big) as the operation
We wish to show that the set \pi_1(X,b):=\frac{\Omega(X,b)}{\big({\small(\cdot)}\simeq{\small (\cdot)}\ (\text{rel }\{0,1\})\big)} is actually a group with the operation \overline{*} as described in the outline.
- Factoring:
- Setup:
- *:\Omega(X,b)\times\Omega(X,b)\rightarrow\Omega(X,b) - the operation of loop concatenation - *:(\ell_1,\ell_2)\mapsto\left(\ell_1*\ell_2:I\rightarrow X\text{ by }\ell_1*\ell_2:t\mapsto\left\{\begin{array}{lr}\ell_1(2t) & \text{for }t\in[0,\frac{1}{2}]\\ \ell(2t-1) & \text{for }t\in[\frac{1}{2},1]\end{array}\right.\right)
- through
- (p,p):\Omega(X,b)\times\Omega(X,b)\rightarrow\pi_1(X,b)\times\pi_1(X,b) by (p,p):(\ell_1,\ell_2)\mapsto(p(\ell_1),p(\ell_2))
- We must show:
- \forall\ell_1,\ell_2,\ell_1',\ell_2'\in\Omega(X,b)\left[\big([\ell_1]=[\ell_1']\wedge[\ell_2]=[\ell_2']\big)\implies\big([\ell_1*\ell_2]=[\ell_1'*\ell_2']\big)\right][Note 1]
- Proof:
- Let \ell_1,\ell_2,\ell_1',\ell_2'\in\Omega(X,b) be given
- Suppose that \neg([\ell_1]=[\ell_1']\wedge[\ell_2]=[\ell_2']) holds, then by the nature of logical implication we're done, as we do not care about the RHS's truth or falsity in this case
- Suppose that [\ell_1]=[\ell_1']\wedge[\ell_2]=[\ell_2'] holds. We must show that in this case we have [\ell_1*\ell_2]=[\ell_1'*\ell_2']
- Since \ell_1,\ell_2,\ell_1' and \ell_2' were arbitrary this holds for all.
- Conclusion
- We obtain \overline{*}:\pi_1(X,b)\times\pi_1(X,b)\rightarrow\pi_1(X,b) given unambiguously by:
- \overline{*}:([\ell_1],[\ell_2])\mapsto[\ell_1*\ell_2]
- Thus the group operation is:
- [\ell_1]\overline{*}[\ell_2]:=[\ell_1*\ell_2]
- Associativity of the operation \overline{*}
- Existence of an identity element in (\pi_1(X,b),\overline{*})
- For each element of \pi_1(X,b) the existence of an inverse element in (\pi_1(X,b),\overline{*})
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Finish this off
References
OLD PAGE
Requires: Paths and loops in a topological space and Homotopic paths
Definition
Given a topological space X and a point x_0\in X the fundamental group is[1]
- forms a group under the operation of multiplication of the homotopy classes.
[Expand]
Theorem: \pi_1(X,x_0) with the binary operation * forms a group[2]
- Identity element
- Inverses
- Association
See Homotopy class for these properties
TODO: Mond p30
See also
References
- Jump up ↑ Introduction to Topology - Second Edition - Theodore W. Gamelin and Rober Everist Greene
- Jump up ↑ Introduction to topology - lecture notes nov 2013 - David Mond
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