Difference between revisions of "Contravariant functor/Definition"
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(Created page with "<noinclude> ==Definition== </noinclude> A ''covariant functor'', {{M|T:C\leadsto D}} (for categories {{M|C}} and {{M|D}}) is a pair of mappings{{rAIRM...") |
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− | A ''covariant functor'', {{M| | + | A ''covariant functor'', {{M|S:C\leadsto D}} (for [[category|categories]] {{M|C}} and {{M|D}}) is a pair of [[mapping|mappings]]{{rAIRMACCF}}: |
* {{M|1=S:\left\{Obj(C)⟶Obj(D)X⟼SX \right. }} | * {{M|1=S:\left\{Obj(C)⟶Obj(D)X⟼SX \right. }} | ||
* {{M|1=S:\left\{Mor(C)⟶Mor(D)f⟼Sf \right. }} | * {{M|1=S:\left\{Mor(C)⟶Mor(D)f⟼Sf \right. }} |
Latest revision as of 16:53, 2 February 2016
Definition
A covariant functor, S:C⇝D (for categories C and D) is a pair of mappings[1]:
- S:{Obj(C)⟶Obj(D)X⟼SX
- S:{Mor(C)⟶Mor(D)f⟼Sf
- Note that if f:A→B then Sf:B→A
Which preserves only the identity morphism of each object - it reverses composition of morphisms, that is to say:
- ∀f,g∈Mor(C)[Sgf=S(g∘f)=Sf∘Sg=SfSg] (I've added the ∘s in to make it more obvious to the reader what is going on)
- Where such composition makes sense. That is target(f)=source(g).
- and ∀A∈Obj(C)[S1A=1SA]
Thus if f:X→Y and g:Y→Z are morphisms of C, then the following diagram commutes:
Thus the diagram just depicts the requirement that:
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Note that the diagram is similar to
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