Difference between revisions of "Singleton (set theory)/Definition"

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==Definition==
 
==Definition==
</noinclude>Let {{M|X}} be a [[set]]. We call {{M|X}} a ''singleton'' if<ref name="War2011">[[Media:WarwcikSetTheoryLectureNotes2011.pdf|Warwick lecture notes - Set Theory - 2011 - Adam Epstein]] - page 2.75.</ref>:
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</noinclude>Let {{M|X}} be a [[set]]. We call {{M|X}} a ''singleton'' if<ref name="War2011">[[Media:WarwickSetTheoryLectureNotes2011.pdf|Warwick lecture notes - Set Theory - 2011 - Adam Epstein]] - page 2.75.</ref>:
 
* {{M|\exists t[t\in X\wedge\forall s(s\in X\rightarrow s\eq t)]}}<sup>{{Caveat|See:}}</sup><ref group="Note">Note that:
 
* {{M|\exists t[t\in X\wedge\forall s(s\in X\rightarrow s\eq t)]}}<sup>{{Caveat|See:}}</sup><ref group="Note">Note that:
 
* {{M|\exists t[t\in X\rightarrow\forall s(s\in X\rightarrow s\eq t)]}}
 
* {{M|\exists t[t\in X\rightarrow\forall s(s\in X\rightarrow s\eq t)]}}

Latest revision as of 23:34, 8 March 2017

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Definition

Let X be a set. We call X a singleton if[1]:

  • t[tXs(sXs=t)]Caveat:See:[Note 1]
    • In words: X is a singleton if: there exists a thing such that ( the thing is in X and for any stuff ( if that stuff is in X then the stuff is the thing ) )

More concisely this may be written:

  • tXsX[t=s][Note 2]

Notes

  1. Jump up Note that:
    • t[tXs(sXs=t)]
    Does not work! As if tX by the nature of logical implication we do not care about the truth or falsity of the right hand side of the first ! Spotted when starting proof of "A pair of identical elements is a singleton"
  2. Jump up see rewriting for-all and exists within set theory

References

  1. Jump up Warwick lecture notes - Set Theory - 2011 - Adam Epstein - page 2.75.