Difference between revisions of "Bounded linear map"
From Maths
(Redirected page to Bounded (linear map)) |
m |
||
(2 intermediate revisions by the same user not shown) | |||
Line 1: | Line 1: | ||
− | + | {{Stub page|needs fleshing out|grade=B}} | |
+ | ==Definition== | ||
+ | Given two [[normed space|normed spaces]] {{M|(X,\Vert\cdot\Vert_X)}} and {{M|(Y,\Vert\cdot\Vert_Y)}} and a [[linear map]] {{M|L:X\rightarrow Y}}, we say that{{rAPIKM}}: | ||
+ | * {{M|L}} is bounded if (and only if) | ||
+ | ** {{M|\exists A\ge 0\ \forall x\in X\left[\Vert L(x)\Vert_Y\le A\Vert x\Vert_X\right]}} | ||
+ | ==See also== | ||
+ | * [[Equivalent conditions for a linear map between two normed spaces to be continuous everywhere]] - of which being bounded is an equivalent statement | ||
+ | |||
+ | ==References== | ||
+ | <references/> | ||
{{Definition|Linear Algebra|Functional Analysis|Topology|Metric Space}} | {{Definition|Linear Algebra|Functional Analysis|Topology|Metric Space}} |
Latest revision as of 21:30, 19 April 2016
Stub grade: B
This page is a stub
This page is a stub, so it contains little or minimal information and is on a to-do list for being expanded.The message provided is:
needs fleshing out
Definition
Given two normed spaces (X,∥⋅∥X) and (Y,∥⋅∥Y) and a linear map L:X→Y, we say that[1]:
- L is bounded if (and only if)
- ∃A≥0 ∀x∈X[∥L(x)∥Y≤A∥x∥X]
See also
- Equivalent conditions for a linear map between two normed spaces to be continuous everywhere - of which being bounded is an equivalent statement